GCSE / O Levels Chemistry

Dilute hydrochloric acid is added separately to samples of copper, copper(II) oxide and
copper(II) carbonate.
Which row correctly shows whether copper(II) chloride is produced?
Cu
Cuo
CuCO3
A
key
B
V= copper(II) chloride produced
X = copper(II) chloride not produced
D


Choice D is correct because:

Copper (Cu) does not react with dilute hydrochloric acid because copper is less reactive than hydrogen and thus can't displace it from the acid. Therefore, no copper(II) chloride is produced, which is correctly indicated by an "X".

Copper(II) oxide (CuO) reacts with hydrochloric acid to produce copper(II) chloride and water. This reaction can be represented by the equation: CuO + 2HCl -> CuCl2 + H2O. So, copper(II) chloride is produced, which is correctly indicated by a "✓".

Copper(II) carbonate (CuCO3) reacts with hydrochloric acid to produce copper(II) chloride, water, and carbon dioxide. This reaction can be represented by the equation: CuCO3 + 2HCl -> CuCl2 + H2O + CO2. So, copper(II) chloride is produced, which is correctly indicated by a "✓".

Choice A is incorrect because copper (Cu) does not react with dilute hydrochloric acid, so copper(II) chloride is not produced. 

Choice B is incorrect because copper(II) carbonate (CuCO3) does react with hydrochloric acid to produce copper(II) chloride.

Choice C is incorrect because copper(II) oxide (CuO) does react with hydrochloric acid to produce copper(II) chloride.

Types of Oxides | 2017 - O/N - 5070/12 | Q24